Simulator 3 of a series · interactive

When does “a missing symmetry explains it” stop being enough?

A good explanation should say where it fails. The paper tested its claim on five tasks, each under three definitions of “trained well enough”. Can you guess where the claim breaks?

PAPERAll numbers come from Tables 5 and 6 of Lakhanpal (2026), v2. Nothing here is simulated.

Step 1 · Predict

Tap the cells where you think the claim fails

“Fails” means the barrier left after searching every permutation and sign flip is above ε = 0.5 points (upper quartile over pairs). Columns are the training-error tolerance used to include networks.

Pick any cells (dashed outline), then reveal.

What the map says

The two failures (pentagon at 1%, hexagon at 5%) are also the cells where many pairs learned different lines. Switch the colour to the same-line share to see it. The link is one-directional: learning the same lines almost always closed the barrier, but different-line pairs sometimes closed too (23 of 58 distinct different-line pairs ended below ε), so the map shows association, not a rule.

Pooled Table 6, exploratory (split decided after seeing results): at 2%, all 157 same-line pairs ended at or below 0.21 points; the 8 different-line pairs kept 2.38–9.58. Over all three thresholds, 328 of 331 distinct same-line pairs ended below ε.

Expert notes

Minimal width h*
The smallest trained width with at least 10 networks under the tolerance; operational, so it changes with the column (e.g. pentagon h* = 5 at 1%, 4 at 2%, 3 at 5%).
Residual
Upper quartile of the exact_sign training-error barrier: best of all 2hh! permutation and flip combinations, chosen by the 25-point barrier. A lower bound on the continuous supremum.
Same-line test
Pairs match when every line agrees within 10° and 0.25 standardized units. Exploratory link to identifiability: irreducible networks computing the same function differ only by permutations and flips (Sussmann).
Caveat
Pairs with a nearly reducible network are excluded (two, hexagon at 5%). Hexagon h* = 4 at 2% is an upper bound.

Full interactive paper page · All simulators · github.com/MrigeshLakhanpal/sign-flips-lmc